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Indian Institute of Banking & Finance conducts diploma of JAIIB and CAIIB for the bankers. The main objective of this diploma is:

• To facilitate study of theory and practice of banking and finance.

• To test and certify attainment of competence in the profession of banking and finance.

• To collect, analyse and provide information needed by professionals in banking and finance.

• To promote continuous professional development.

• To promote and undertake research relating to Operations, Products, Instruments, Processes, etc. In banking and finance and to encourage innovation and creativity among finance professionals so That they could face competition and succeed.

The exam is held twice in a year in the month of May and November-December. You have to clear all the papers of JAIIB before applying for CAIIB. Here is free study material for both JAIIB and CAIIB exams.

JAIIB contains three papers viz

• 1. Principles & Practices of Banking

• 2. Accounting & Finance for Bankers

• 3. Legal and Regulatory Aspects of Banking

You can download the e-text format of aforementioned JAIIB books from 

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here. If you are not comfortable with the e-text format, you can download the audio format of the books of JAIIB recorded by samerita trust from

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CAIIB also contains three papers viz

• 1. Advance Bank Management

• 2. Bank Financial Management

• 3. Retail Banking

Regarding the third paper, candidates can choose one paper from the eleven optional papers that will now be offered as electives. The electives cover the entire range of specialized domains in a bank. The electives currently offered are Human Resources Management, Risk, Treasury, Retail Banking, International Banking, Corporate Banking, Co-operative Banking, Information Technology, Rural Banking, Financial Advising and Central Banking.You can download the aforemention material of CAIIB in text from 

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1.2MB .zip

here. Material in audio format, recorded by Samrita Trust, is also available here.

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ALL IMPORTANT FORMULAS

Some Useful Chapter wise Formulas : Like & Share Post
==============================================

1. Sum of first n natural numbers = n(n+1)/2
2. Sum of the squares of first n natural numbers = n(n+1)(2n+1)/6
3. Sum of the cubes of first n natural numbers = [n(n+1)/2]^2
4. Sum of first n natural odd numbers = n^2
5. Average = (Sum of items)/Number of items

Arithmetic Progression (A.P.):
==========================
An A.P. is of the form a, a+d, a+2d, a+3d, …
where a is called the ‘first term’ and d is called the ‘common difference’
1. nth term of an A.P. tn = a + (n-1)d
2. Sum of the first n terms of an A.P. Sn = n/2[2a+(n-1)d] or Sn = n/2(first term + last term)

Geometrical Progression (G.P.):
============================
A G.P. is of the form a, ar, ar2, ar3, …
where a is called the ‘first term’ and r is called the ‘common ratio’.
1. nth term of a G.P. tn = arn-1
2. Sum of the first n terms in a G.P. Sn = a|1-rn|/|1-r|

Permutations and Combinations :
===============================
nPr = n!/(n-r)!
nPn = n!
nP1 = n
nCr = n!/(r! (n-r)!)
nC1 = n
nC0 = 1 = nCn
nCr = nCn-r
nCr = nPr/r!
Number of diagonals in a geometric figure of n sides = nC2-n

Tests of Divisibility :
=======================
A number is divisible by 2 if it is an even number.
A number is divisible by 3 if the sum of the digits is divisible by 3.
A number is divisible by 4 if the number formed by the last two digits is divisible by 4.
A number is divisible by 5 if the units digit is either 5 or 0.
A number is divisible by 6 if the number is divisible by both 2 and 3.
A number is divisible by 8 if the number formed by the last three digits is divisible by 8.
A number is divisible by 9 if the sum of the digits is divisible by 9.
A number is divisible by 10 if the units digit is 0.
A number is divisible by 11 if the difference of the sum of its digits at odd places and the sum of its digits at even places, is divisible by 11.
H.C.F and L.C.M :
H.C.F stands for Highest Common Factor. The other names for H.C.F are Greatest Common Divisor (G.C.D) and Greatest Common Measure (G.C.M).
The H.C.F. of two or more numbers is the greatest number that divides each one of them exactly.
The least number which is exactly divisible by each one of the given numbers is called their L.C.M.
Two numbers are said to be co-prime if their H.C.F. is 1.
H.C.F. of fractions = H.C.F. of numerators/L.C.M of denominators
L.C.M. of fractions = G.C.D. of numerators/H.C.F of denominators
Product of two numbers = Product of their H.C.F. and L.C.M.

PERCENTAGES :
================
If A is R% more than B, then B is less than A by R / (100+R) * 100
If A is R% less than B, then B is more than A by R / (100-R) * 100
If the price of a commodity increases by R%, then reduction in consumption, not to increase the expenditure is : R/(100+R)*100
If the price of a commodity decreases by R%, then the increase in consumption, not to decrease the expenditure is : R/(100-R)*100

PROFIT & LOSS :
======================
Gain = Selling Price(S.P.) – Cost Price(C.P)
Loss = C.P. – S.P.
Gain % = Gain * 100 / C.P.
Loss % = Loss * 100 / C.P.
S.P. = (100+Gain%)/100*C.P.
S.P. = (100-Loss%)/100*C.P.
If CP(x), Gain(y), Gain%(z). Then y = x*z/100. [Same in case of Loss]

RATIO & PROPORTIONS:
==========================
The ratio a : b represents a fraction a/b. a is called antecedent and b is called consequent.
The equality of two different ratios is called proportion.
If a : b = c : d then a, b, c, d are in proportion. This is represented by a : b :: c : d.
In a : b = c : d, then we have a* d = b * c.
If a/b = c/d then ( a + b ) / ( a – b ) = ( c + d ) / ( c – d ).

TIME & WORK :
===================
If A can do a piece of work in n days, then A’s 1 day’s work = 1/n
If A and B work together for n days, then (A+B)’s 1 days’s work = 1/n
If A is twice as good workman as B, then ratio of work done by A and B = 2:1

PIPES & CISTERNS :
=====================
If a pipe can fill a tank in x hours, then part of tank filled in one hour = 1/x
If a pipe can empty a full tank in y hours, then part emptied in one hour = 1/y
If a pipe can fill a tank in x hours, and another pipe can empty the full tank in y hours, then on opening both the pipes,
the net part filled in 1 hour = (1/x-1/y) if y>x
the net part emptied in 1 hour = (1/y-1/x) if x>y

TIME & DISTANCE :
=======================
Distance = Speed * Time
1 km/hr = 5/18 m/sec
1 m/sec = 18/5 km/hr
Suppose a man covers a certain distance at x kmph and an equal distance at y kmph. Then, the average speed during the whole journey is 2xy/(x+y) kmph.

PROBLEMS ON TRAINS :
=========================
Time taken by a train x metres long in passing a signal post or a pole or a standing man is equal to the time taken by the train to cover x metres.
Time taken by a train x metres long in passing a stationary object of length y metres is equal to the time taken by the train to cover x+y metres.
Suppose two trains are moving in the same direction at u kmph and v kmph such that u>v, then their relative speed = u-v kmph.
If two trains of length x km and y km are moving in the same direction at u kmph and v kmph, where u>v, then time taken by the faster train to cross the slower train = (x+y)/(u-v) hours.
Suppose two trains are moving in opposite directions at u kmph and v kmph. Then, their relative speed = (u+v) kmph.
If two trains of length x km and y km are moving in the opposite directions at u kmph and v kmph, then time taken by the trains to cross each other = (x+y)/(u+v)hours.
If two trains start at the same time from two points A and B towards each other and after crossing they take a and b hours in reaching B and A respectively, then A’s speed : B’s speed = (√b : √a)

SIMPLE & COMPOUND INTERESTS :
===================================
Let P be the principal, R be the interest rate percent per annum, and N be the time period.
Simple Interest = (P*N*R)/100
Compound Interest = P(1 + R/100)^N – P
Amount = Principal + Interest
when rate of interest time n principal are constant den principal=(C.I.-S.I.)*(100/R)^N

LOGORITHMS :
====================
If a^m = x , then m = loga(x).
Properties :
logx(x) = 1
logx(1) = 0
loga(x*y) = loga(x) + loga(y)
loga(x/y) = log ax – log ay
loga(x) = 1/logx(a)
loga(x^p) = p(loga(x))
loga(x) = logb(x)/logb(a)
Note : Logarithms for base 1 does not exist.

AREA & PERIMETER :
===================
Shape Area Perimeter
Circle ∏ (Radius)2 2∏(Radius)
Square (side)2 4(side)
Rectangle length*breadth 2(length+breadth)
Area of a triangle = 1/2*Base*Height or
Area of a triangle = √ (s(s-(s-b)(s-c)) where a,b,c are the lengths of the sides and s = (a+b+c)/2
Area of a parallelogram = Base * Height
Area of a rhombus = 1/2(Product of diagonals)
Area of a trapezium = 1/2(Sum of parallel sides)(distance between the parallel sides)
Area of a quadrilateral = 1/2(diagonal)(Sum of sides)
Area of a regular hexagon = 6(√3/4)(side)2
Area of a ring = ∏(R2-r2) where R and r are the outer and inner radii of the ring.
Area of a circle=πr^2 or πd^2/4
Area of semi-circle=πr^2/2
Area of a quadrant of a circle=πr^2/4
Area enclosed by two concentric circles=π(R^2-r^2)
Area of a sector=Ɵ/180 degree *πr
No of revolutions completed by a rotating wheel in 1 minute=distance moved in 1 minute/circumference

VOLUME & SURFACE AREA :
============================
* Cube :
Let a be the length of each edge. Then,
Volume of the cube = a3 cubic units
Surface Area = 6a2 square units
Diagonal = √ 3 a units
* Cuboid :
Let l be the length, b be the breadth and h be the height of a cuboid. Then
Volume = lbh cu units
Surface Area = 2(lb+bh+lh) sq units
Diagonal = √ (l2+b2+h2)
* Cylinder :
Let radius of the base be r and height of the cylinder be h. Then,
Volume = ∏r2h cu units
Curved Surface Area = 2∏rh sq units
Total Surface Area = 2∏rh + 2∏r2 sq units
* Cone :
Let r be the radius of base, h be the height, and l be the slant height of the cone. Then,
l2 = h2 + r2
Volume = 1/3(∏r2h) cu units
Curved Surface Area = ∏rl sq units
Total Surface Area = ∏rl + ∏r2 sq units
* Sphere :
Let r be the radius of the sphere. Then,
Volume = (4/3)∏r3 cu units
Surface Area = 4∏r2 sq units
Hemi - sphere :
Let r be the radius of the hemi - sphere. Then,
Volume = (2/3)∏r3 cu units
Curved Surface Area = 2∏r2 sq units
Total Surface Area = 3∏r2 sq units
* Prism :
Volume = (Area of base)(Height)

ALGEBRA
============
1.(a+b)^2=a^2+2ab+b^2
2.(a-b)^2=a^2-2ab+b^2
3.(a+b)^2=(a-b)^2+4ab
4.(a-b)^2=(a+b)^2-4ab
5.a^2-b^2=(a+b)(a-b)
6.(a + b)3= a3+ b3+ 3ab(a + b)
7.a3+ b3= (a + b)3− 3ab(a + b);(a+b)^3-3ab(a+b)
8.(a − b)3= a3− b3− 3ab(a − b)
9.a3− b3= (a − b)3+ 3ab(a − b);(a-b)^3+3ab(a-b)
10.a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ac)
=(a+b+c)*1/2*[(a-b)^2+(b-c)^2+(c-a)^2]
11.if a+b+c=0 then a^3+b^3+c^3=3abc
12.(a+b+c)^3=a^3+b^3+c^3+3(b+c)(c+a)(a+b)
13.a^2+b^2=(a+b)^2-2ab=(a-b)^2+2ab
14.(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)
15.. a^n− b^n= (a − b)(a^n−1+ a^n−2*b + a^n−3*b^2+ …..+b^n−1)

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ALL IMPORTANT FORMULAS

Some Useful Chapter wise Formulas : Like & Share Post
==============================================

1. Sum of first n natural numbers = n(n+1)/2
2. Sum of the squares of first n natural numbers = n(n+1)(2n+1)/6
3. Sum of the cubes of first n natural numbers = [n(n+1)/2]^2
4. Sum of first n natural odd numbers = n^2
5. Average = (Sum of items)/Number of items

Arithmetic Progression (A.P.):
==========================
An A.P. is of the form a, a+d, a+2d, a+3d, …
where a is called the ‘first term’ and d is called the ‘common difference’
1. nth term of an A.P. tn = a + (n-1)d
2. Sum of the first n terms of an A.P. Sn = n/2[2a+(n-1)d] or Sn = n/2(first term + last term)

Geometrical Progression (G.P.):
============================
A G.P. is of the form a, ar, ar2, ar3, …
where a is called the ‘first term’ and r is called the ‘common ratio’.
1. nth term of a G.P. tn = arn-1
2. Sum of the first n terms in a G.P. Sn = a|1-rn|/|1-r|

Permutations and Combinations :
===============================
nPr = n!/(n-r)!
nPn = n!
nP1 = n
nCr = n!/(r! (n-r)!)
nC1 = n
nC0 = 1 = nCn
nCr = nCn-r
nCr = nPr/r!
Number of diagonals in a geometric figure of n sides = nC2-n

Tests of Divisibility :
=======================
A number is divisible by 2 if it is an even number.
A number is divisible by 3 if the sum of the digits is divisible by 3.
A number is divisible by 4 if the number formed by the last two digits is divisible by 4.
A number is divisible by 5 if the units digit is either 5 or 0.
A number is divisible by 6 if the number is divisible by both 2 and 3.
A number is divisible by 8 if the number formed by the last three digits is divisible by 8.
A number is divisible by 9 if the sum of the digits is divisible by 9.
A number is divisible by 10 if the units digit is 0.
A number is divisible by 11 if the difference of the sum of its digits at odd places and the sum of its digits at even places, is divisible by 11.
H.C.F and L.C.M :
H.C.F stands for Highest Common Factor. The other names for H.C.F are Greatest Common Divisor (G.C.D) and Greatest Common Measure (G.C.M).
The H.C.F. of two or more numbers is the greatest number that divides each one of them exactly.
The least number which is exactly divisible by each one of the given numbers is called their L.C.M.
Two numbers are said to be co-prime if their H.C.F. is 1.
H.C.F. of fractions = H.C.F. of numerators/L.C.M of denominators
L.C.M. of fractions = G.C.D. of numerators/H.C.F of denominators
Product of two numbers = Product of their H.C.F. and L.C.M.

PERCENTAGES :
================
If A is R% more than B, then B is less than A by R / (100+R) * 100
If A is R% less than B, then B is more than A by R / (100-R) * 100
If the price of a commodity increases by R%, then reduction in consumption, not to increase the expenditure is : R/(100+R)*100
If the price of a commodity decreases by R%, then the increase in consumption, not to decrease the expenditure is : R/(100-R)*100

PROFIT & LOSS :
======================
Gain = Selling Price(S.P.) – Cost Price(C.P)
Loss = C.P. – S.P.
Gain % = Gain * 100 / C.P.
Loss % = Loss * 100 / C.P.
S.P. = (100+Gain%)/100*C.P.
S.P. = (100-Loss%)/100*C.P.
If CP(x), Gain(y), Gain%(z). Then y = x*z/100. [Same in case of Loss]

RATIO & PROPORTIONS:
==========================
The ratio a : b represents a fraction a/b. a is called antecedent and b is called consequent.
The equality of two different ratios is called proportion.
If a : b = c : d then a, b, c, d are in proportion. This is represented by a : b :: c : d.
In a : b = c : d, then we have a* d = b * c.
If a/b = c/d then ( a + b ) / ( a – b ) = ( c + d ) / ( c – d ).

TIME & WORK :
===================
If A can do a piece of work in n days, then A’s 1 day’s work = 1/n
If A and B work together for n days, then (A+B)’s 1 days’s work = 1/n
If A is twice as good workman as B, then ratio of work done by A and B = 2:1

PIPES & CISTERNS :
=====================
If a pipe can fill a tank in x hours, then part of tank filled in one hour = 1/x
If a pipe can empty a full tank in y hours, then part emptied in one hour = 1/y
If a pipe can fill a tank in x hours, and another pipe can empty the full tank in y hours, then on opening both the pipes,
the net part filled in 1 hour = (1/x-1/y) if y>x
the net part emptied in 1 hour = (1/y-1/x) if x>y

TIME & DISTANCE :
=======================
Distance = Speed * Time
1 km/hr = 5/18 m/sec
1 m/sec = 18/5 km/hr
Suppose a man covers a certain distance at x kmph and an equal distance at y kmph. Then, the average speed during the whole journey is 2xy/(x+y) kmph.

PROBLEMS ON TRAINS :
=========================
Time taken by a train x metres long in passing a signal post or a pole or a standing man is equal to the time taken by the train to cover x metres.
Time taken by a train x metres long in passing a stationary object of length y metres is equal to the time taken by the train to cover x+y metres.
Suppose two trains are moving in the same direction at u kmph and v kmph such that u>v, then their relative speed = u-v kmph.
If two trains of length x km and y km are moving in the same direction at u kmph and v kmph, where u>v, then time taken by the faster train to cross the slower train = (x+y)/(u-v) hours.
Suppose two trains are moving in opposite directions at u kmph and v kmph. Then, their relative speed = (u+v) kmph.
If two trains of length x km and y km are moving in the opposite directions at u kmph and v kmph, then time taken by the trains to cross each other = (x+y)/(u+v)hours.
If two trains start at the same time from two points A and B towards each other and after crossing they take a and b hours in reaching B and A respectively, then A’s speed : B’s speed = (√b : √a)

SIMPLE & COMPOUND INTERESTS :
===================================
Let P be the principal, R be the interest rate percent per annum, and N be the time period.
Simple Interest = (P*N*R)/100
Compound Interest = P(1 + R/100)^N – P
Amount = Principal + Interest
when rate of interest time n principal are constant den principal=(C.I.-S.I.)*(100/R)^N

LOGORITHMS :
====================
If a^m = x , then m = loga(x).
Properties :
logx(x) = 1
logx(1) = 0
loga(x*y) = loga(x) + loga(y)
loga(x/y) = log ax – log ay
loga(x) = 1/logx(a)
loga(x^p) = p(loga(x))
loga(x) = logb(x)/logb(a)
Note : Logarithms for base 1 does not exist.

AREA & PERIMETER :
===================
Shape Area Perimeter
Circle ∏ (Radius)2 2∏(Radius)
Square (side)2 4(side)
Rectangle length*breadth 2(length+breadth)
Area of a triangle = 1/2*Base*Height or
Area of a triangle = √ (s(s-(s-b)(s-c)) where a,b,c are the lengths of the sides and s = (a+b+c)/2
Area of a parallelogram = Base * Height
Area of a rhombus = 1/2(Product of diagonals)
Area of a trapezium = 1/2(Sum of parallel sides)(distance between the parallel sides)
Area of a quadrilateral = 1/2(diagonal)(Sum of sides)
Area of a regular hexagon = 6(√3/4)(side)2
Area of a ring = ∏(R2-r2) where R and r are the outer and inner radii of the ring.
Area of a circle=πr^2 or πd^2/4
Area of semi-circle=πr^2/2
Area of a quadrant of a circle=πr^2/4
Area enclosed by two concentric circles=π(R^2-r^2)
Area of a sector=Ɵ/180 degree *πr
No of revolutions completed by a rotating wheel in 1 minute=distance moved in 1 minute/circumference

VOLUME & SURFACE AREA :
============================
* Cube :
Let a be the length of each edge. Then,
Volume of the cube = a3 cubic units
Surface Area = 6a2 square units
Diagonal = √ 3 a units
* Cuboid :
Let l be the length, b be the breadth and h be the height of a cuboid. Then
Volume = lbh cu units
Surface Area = 2(lb+bh+lh) sq units
Diagonal = √ (l2+b2+h2)
* Cylinder :
Let radius of the base be r and height of the cylinder be h. Then,
Volume = ∏r2h cu units
Curved Surface Area = 2∏rh sq units
Total Surface Area = 2∏rh + 2∏r2 sq units
* Cone :
Let r be the radius of base, h be the height, and l be the slant height of the cone. Then,
l2 = h2 + r2
Volume = 1/3(∏r2h) cu units
Curved Surface Area = ∏rl sq units
Total Surface Area = ∏rl + ∏r2 sq units
* Sphere :
Let r be the radius of the sphere. Then,
Volume = (4/3)∏r3 cu units
Surface Area = 4∏r2 sq units
Hemi - sphere :
Let r be the radius of the hemi - sphere. Then,
Volume = (2/3)∏r3 cu units
Curved Surface Area = 2∏r2 sq units
Total Surface Area = 3∏r2 sq units
* Prism :
Volume = (Area of base)(Height)

ALGEBRA
============
1.(a+b)^2=a^2+2ab+b^2
2.(a-b)^2=a^2-2ab+b^2
3.(a+b)^2=(a-b)^2+4ab
4.(a-b)^2=(a+b)^2-4ab
5.a^2-b^2=(a+b)(a-b)
6.(a + b)3= a3+ b3+ 3ab(a + b)
7.a3+ b3= (a + b)3− 3ab(a + b);(a+b)^3-3ab(a+b)
8.(a − b)3= a3− b3− 3ab(a − b)
9.a3− b3= (a − b)3+ 3ab(a − b);(a-b)^3+3ab(a-b)
10.a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ac)
=(a+b+c)*1/2*[(a-b)^2+(b-c)^2+(c-a)^2]
11.if a+b+c=0 then a^3+b^3+c^3=3abc
12.(a+b+c)^3=a^3+b^3+c^3+3(b+c)(c+a)(a+b)
13.a^2+b^2=(a+b)^2-2ab=(a-b)^2+2ab
14.(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)
15.. a^n− b^n= (a − b)(a^n−1+ a^n−2*b + a^n−3*b^2+ …..+b^n−1)

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FRIENDS I AM POSTING HERE DIRECT LINK FOR TAKING YOUR ADMIT CARD OF RBI

ASSISTANTS TO BE HELD ON VARIOUS DATES OF 4TH WEEK OF SEPTEMBER

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ESSENTIAL BOOKS FOR IAS EXAM


EVERYONE DREAMS ABOUT THE PASSION TO BECOME IAS IFS OR BEST INDIAN SERVICES TO WORK WITH SO HERE WE ARE PROVIDING BEST BOOK LIST TO BUY FROM GREAT SITES FOR CHEAP COST SPECIALLY FOR YOU . IF YOU ARE IN A CONFUSION WHICH BOOKS TO BUY JUST GO WITH THIS SIMPLY SPECIALLY SAID BY IAS SENIOR OFFICIALS AND ASPIRANTS

  History of Modern India


 India's Struggle for Independence

YOU SHOULD READ BOTH BOOKS FOR BEST IDEA IN HISTORY


Facets of Indian Culture

IT GIVES EXCELLENT EXPLANATION REGARDING ART CULTURE AND DANCE WHICH
PLAYED A MOST IMPORTANT ROLE IN PRELIMS IAS 2014


Geography of India BEST BOOK AS MOST OF THEM PREFER FOR GEOGRAPHY



Oxford School Atlas
 ATLAS IS REQUIRED FOR BOTH GEOGRAPHY AND SCIENCE RELATED QUESTIONS


Certificate Physical and Human Geography

BEST BOOK WITH SMALL OR FEW PAGES VERY GOOD UNDERSTANDING TOO

MAJID HUSSAIN GEOGRAPHY AND THIS BOOK BOTH ARE NEEDED FOR PHYSICAL AND HUMAN GEOGRAPHY RESPECTIVELY.


Indian Polity Indian Economy

LAXMIKANTH POLITY BOOK JUST YOU FELL IN LOVE WITH IT I BET YOU WONT STOP READING UNTIL YOU COMPLETE IT



  Economic Survey 2013-14 (Set of 2 Vols.)

ALWAYS PRECRIBED BEST AUTHOR


IBPS Bank PO/MT/SO Probationary Officer/Management Trainee/Specialist Officer CWE - 4 Self Study Guide-Cum-Practice Work Book (With CD) Based on Online Exam pattern



  Developments in Science and Technology India 2014



IF YOU FOLLOW SOME WEBSITES FOR SCIENCE AND TECH THIS IS NOT NECESSARY BUT ONE SMALL SUGESTION THAT INDIA YEAR BOOK CONTAINS OFF THE TOPICS OF CURRENT AFFAIRS IN SCIENCE AND TECHNOLOGY SO BETTER TO BUY IT

 Manorama Yearbook 2014 (Book & CD)

  Cracking the CSAT Paper - 2 A Modern Approach to Verbal & Non-Verbal Reasoning

ARIHANT CSAT BOOKS WILL GIVE EXCELLENT APPROACH TO ANY EXAMSOLVING TECHNIQUES ADDITIONAL BOOKS FOR IAS ASPIRANTS FOR REMAINING PAPERS


  UPSC-Civil Services Main-Issues Relating to Social Development:


IAS G.S. (New Syllabus)


  UPSC-Civil Services Main-Issues Relating to Social Development: IAS G.S. (New Syllabus)


  Pax Indica: India and the World of the 21st Century


Ethics in Governance: Innovations, Issues and Instrumentalities


Ethics, Integrity and Aptitude: For Civil Services Main Examination Paper V